Reasons and solutions for unbalanced load of weighing sensor of electronic platform scale.

The eccentric load of the weighing sensor of the electronic platform scale refers to the error caused by the inconsistency between the weighing output of adding a weight at the center of the pricing scale and adding the same weight at the off center position of the scale. Most of the printable price platform scales use sensors in the form of parallel beams. Because of the error of the placement and the size inconsistency in the processing, the eccentric load error occurs. Due to the moisture-proof sealing of the sensor after the placement, and the high cost of the strain gauge, the error of the placement cannot be adjusted. From the principle of force deformation of parallel beam, the eccentric load caused by placement error can be attributed to the impact of size inconsistency, so we only need to make size correction.

Common adjustment and repair methods for eccentric load of weighing sensor of electronic platform scale

1. Technicians can grind each stress concentration surface with grinding wheel;

2. File the stress concentration surface with a file;

3. Sand the stress concentration surface with a small sand blasting gun.

The correction of the eccentric load error of the electronic platform scale In order to correct it better and more conveniently, edit the correction points of the parallel beam sensor and number the correction positions. According to the test and analysis, we divide the correction of eccentric load error into the following 6 cases.

When the loading plate is rotated to A, B, C, D, the outputs are:

1. The difference between bit A and bit C is small, bit B is small, and bit D is large. At this time, use a file to file 1 point, 1 'point or 2 points, 2' point.

2. The difference between bit A and bit C is small, bit B is large, and bit D is small. At this time, use a file to file 3 points, 3 'points or 4 points, 4' points.

3. The difference between bit B and bit D is small, bit C is large, and bit A is small. At this time, use a file to file 4, points or 3 'points diagonally.

4. The difference between bit B and bit D is small, bit C is small, and bit A is large. At this time, 4 or 3 points shall be filed obliquely.

5. Bit A is large, bit B is large, bit C is small, and bit D is small., At this time, 4 points are filed diagonally.